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Print alphabet pattern ‘S’ in Python

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To print the alphabet pattern ‘S’ in Python

Code:

for row in range(7):
    for col in range(5):
        if (row in {0, 3, 6}) and (col in {1, 2, 3}):
            print('*', end=' ')
        elif (row in {1, 5}) and (col in {0, 4}):
            print('*', end=' ')
        elif (row == 2) and (col == 0):
            print('*', end=' ')
        elif (row == 4) and (col == 4):
            print('*', end=' ')
        else:
            print(' ', end=' ')
    print()

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